reasoning
Let me analyze this problem:
1. We have a CSR-formatted graph with `row_ptr` and `col_idx`
2. We need to compute per-destination max aggregation over neighbor features
3. The reference is a Python loop that for each destination node, gets its neighbors via `col_idx[start:end]`, indexes into `node_feat`, and computes `amax(dim=0)`
4. Dimensions: num_nodes=640, avg_degree=16, feat_dim=80
GPU specs: NVIDIA H100 with 3.35 TB/s memory bandwidth, 67 FP32 TFLOPS.
The key to optimization here:
- The reference is a sequential Python loop over nodes
- We can parallelize over both destinations and feature dimensions
- Since num_nodes=640 and feat_dim=80, there are 640*80=51200 independent "max reductions"
- Each reduction is over a variable number of neighbors (avg degree ~16)
Strategy:
- Use one thread (or a small group of threads) per (dst, feat_dim) pair
- Each thread computes the maximum over all neighbors for that (dst, feat_dim)
- This is easily parallelizable and memory-bound
Let me think about the kernel design:
Option 1: One thread per (dst, feat)
- Each thread iterates through all neighbors of dst and tracks the max for its feature
- Total threads: num_nodes * feat_dim = 51200
- This is actually quite few threads. We might want a different approach.
Option 2: One warp per dst, or multiple warps per dst
- But feat_dim is only 80, which is less than a warp (32)
Option 3: One block per dst, threads process features
- 640 blocks
- Each block processes feat_dim=80 features
- Could use 128 threads per block, each handling a subset of features or doing vectorized loads
Actually, let me think more carefully. With avg_degree=16 and feat_dim=80:
- Each neighbor feature load is 80 floats = 320 bytes
- For 640*16 = 10240 edges, total neighbor feature memory is ~3.2 MB
- But we also have random access through col_idx
Wait, there's a caching consideration. Since `node_feat` is accessed via `col_idx`, which is random, caching may not be very effective. However, each node is accessed ~16 times on average (640 nodes * 16 accesses / 640 nodes = 16 times each).
Actually, let me reconsider the total work:
- 640 destinations * ~16 neighbors * 80 features = ~819,200 float comparisons
- This is a tiny amount of compute
- The bottleneck is memory bandwidth - reading col_idx and node_feat
Since the problem is memory-bound, we want to maximize memory throughput.
Let me think about the kernel:
```cuda
__global__ void max_agg_kernel(
const int32_t* row_ptr,
const int32_t* col_idx,
const float* node_feat,
float* out,
int num_nodes,
int feat_dim
) {
int dst = blockIdx.x;
int feat = threadIdx.x;
if (dst >= num_nodes || feat >= feat_dim) return;
int start = row_ptr[dst];
int end = row_ptr[dst + 1];
float max_val = -INFINITY;
for (int e = start; e < end; e++) {
int src = col_idx[e];
float val = node_feat[src * feat_dim + feat];
max_val = fmaxf(max_val, val);
}
out[dst * feat_dim + feat] = max_val;
}
```
With 640 blocks and 128 threads per block (to cover 80 features), we'd have 640*128 = 81920 threads. But only 640*80 = 51200 do useful work.
Alternatively, we could process multiple features per thread:
- 640 blocks, 32 threads per block
- Each thread handles 80/32 = 2 or 3 features
- Actually 32*2 = 64, 32*3 = 96, so some threads handle 2 features and some 3
Or we could process multiple destinations per block or use a 2D grid.
Actually, let me think about this more. On H100, we want at least enough warps to keep the SMs busy. With 640 blocks, if each block has at least one warp, we get 640 warps. With 132 SMs (H100 has 132 or 144 SMs depending on config, let me check... actually, H100 SXM5 has 132 SMs), 640 warps should be enough.
But 640 blocks may not saturate the GPU if each block is too small. We might want more parallelism.
Better option: grid-stride loop or process multiple destinations per block.
Let me think of another approach:
- Each block processes one destination node
- Within the block, threads collaboratively load neighbor indices and then features
- Use shared memory to store neighbor indices? With max degree maybe ~20, that's tiny.
Actually, looking at the degree computation:
```python
degree = torch.full((num_nodes,), avg_degree, dtype=torch.int32)
degree = torch.clamp(degree + ((torch.arange(num_nodes, dtype=torch.int32) % 7) - 3), min=1)
```
So degrees range from 13 to 19 (16 + (-3 to 3)), all at least 1. Max degree is 19.
With max degree 19, each destination has at most 19 neighbors. This is very small.
For such small reductions, the best approach might be:
- One thread per (dst, feat) pair
- Each thread directly iterates over all neighbors
Or we can vectorize loads: each thread handles multiple features.
Let me design a kernel with 2D grid:
- x-dimension: feature groups (each group handles e.g., 4 features with vectorized float4 loads)
- y-dimension: destination nodes
With float4, we can process 4 features at once. 80/4 = 20 feature groups.
Grid: (20, 640)
Each thread handles 4 features for one destination.
For edge list, degree is <=19. We process each neighbor:
- Load col_idx[e]
- Load float4 from node_feat[src * feat_dim + feat_group * 4]
- Compute elementwise max
With 640*20 = 12800 threads, this might be a bit light. But float4 gives 4x work per thread.
Alternatively, we could use 1D grid and have each thread handle a (dst, feat) pair. With 51200 threads, that's more parallelism.
Actually, let's think about memory access patterns. The reference accesses `node_feat[col_idx[start:end]]`. This means:
1. Read col_idx[start:end] (sequential within each dst)
2. For each neighbor, read node_feat[src, :] (scattered)
If multiple destinations share neighbors, there could be cache reuse. But with random col_idx and 640 nodes, overlap is probabilistic.
For the kernel, I think a simple approach will work well:
- Use a 2D grid: blocks in x for feature dimension, blocks in y for nodes
- Or 1D grid with block size 256, each thread computing one (dst, feat)
Actually, since the reduction dimension (degree) is small, and the output dimensions (640*80=51200) are modest, we want to make sure we launch enough threads.
Let me try this kernel design:
```cuda
__global__ void max_agg_kernel(
const int* row_ptr,
const int* col_idx,
const float* node_feat,
float* out,
int num_nodes,
int feat_dim
) {
int idx = blockIdx.x * blockDim.x + threadIdx.x;
int total = num_nodes * feat_dim;
while (idx < total) {
int dst = idx / feat_dim;
int feat = idx % feat_dim;
int start = row_ptr[dst];
int end = row_ptr[dst + 1];
float max_val = -INFINITY;
for (int e = start; e < end; e++) {
int src = col_idx[e];
float val = node_feat[src * feat_dim + feat];
max_val = fmaxf(max_val, val);
}
out[idx] = max_val;
idx += gridDim.x * blockDim.x;
}
}
```
This is grid-stride loop. We can launch e.g., 128 blocks * 256 threads = 32768 threads, and each does 51200/32768 ≈ 1.56 iterations on average.
But wait - for the H100, random access to node_feat might benefit from having threads in the same warp access the same neighbor (to exploit cache). In the above design, threads in the same warp access different features of the same dst... no wait, with idx = blockIdx.x * blockDim.x + threadIdx.x, consecutive threads have consecutive idx, so if feat_dim=80, then thread 0 accesses (dst=0, feat=0), thread 1 accesses (dst=0, feat=1), ..., thread 79 accesses (dst=0, feat=79), thread 80 accesses (dst=1, feat=0).
If we have a warp of 32 threads, they access 32 consecutive features for the same dst (or across dst boundary). These accesses are strided by feat_dim floats = 320 bytes. Not great coalescing within a warp when accessing node_feat[src * feat_dim + feat].
Actually, wait. Consecutive threads accessing `node_feat[src * feat_dim + feat]` where `feat` differs by 1 - these are consecutive floats! So they ARE coalesced. Good.
But consecutive threads may be accessing different dsts if warp spans across dst boundary. For thread 64-95, if feat_dim=80, thread 64 is (dst=0, feat=64), thread 65 is (dst=0, feat=65), ..., thread 79 is (dst=0, feat=79), thread 80 is (dst=1, feat=0). So in a warp, threads 64-95 access features 64-79 of dst=0 and features 0-15 of dst=1. The ones accessing dst=0 are coalesced, and the ones accessing dst=1 are coalesced - but the whole warp is accessing two different dsts, which means two different sets of neighbors and two different src nodes. This is fine because each thread independently iterates.
However, there's a better memory access pattern: have all threads in a block/warp work on the same dst, with consecutive features. This way, when we load `col_idx[e]`, all threads use the same `src` (broadcast from L1 cache), and then they access consecutive features of that `src`. This is very cache-friendly.
Let me redesign:
- Block size: 128 threads (or 256, or 128 to maximize occupancy)
- Each block processes one dst
- Thread i in the block processes features i, i+blockDim.x, i+2*blockDim.x, ...
- Actually, for feat_dim=80 and blockDim=128, each thread processes just 1 feature (or some zero)
- Better: blockDim = 128, each thread handles feat_dim/blockDim = 80/128 = 0 or 1... not great.
Actually, we can just use blockDim = 80 or 128 and have each thread handle ceil(80/blockDim.x) features.
Wait, 80 is small. Let's use blockDim = 32 or 64.
- blockDim = 32: each thread handles 80/32 = 2 or 3 features
- blockDim = 64: each thread handles 2 features (or 1 for some)
But actually, since max degree is only ~19, each thread only does ~19 loads. If each thread handles 2-3 features, that's ~40-60 loads per thread. With 640 blocks, that's not a lot of work.
Alternative: launch multiple blocks per dst? That seems unnecessary.
What if we process multiple dsts per block? Say 4 dsts per block, with 32 threads per dst = 128 threads total. Each warp handles one dst. This gives us 640/4 = 160 blocks. Still a bit few.
Actually, on H100, occupancy isn't the main issue for memory-bound kernels - we just need enough warps to hide latency. 640 warps (one per dst with 32 threads) is plenty.
Let me think about a warp-centric design:
- One warp (32 threads) per dst
- Thread i processes features i, i+32, i+64 (since feat_dim=80, third one only if i < 16)
- Actually, 80 = 32*2 + 16, so:
- Threads 0-15 process features tid, tid+32, tid+64 (3 features)
- Threads 16-31 process features tid, tid+32 (2 features)
With one warp per dst, we have 640 warps total. Each warp collaboratively loads col_idx, then all threads access node_feat for the loaded src with broadcast of src and coalesced feature access.
This is actually very efficient:
1. Load col_idx[e]: broadcast to all threads in warp (via L1)
2. All threads load node_feat[src * feat_dim + feat_for_this_thread]: coalesced
3. Update max
We can use __syncwarp() between neighbors if needed, but since there's no data sharing between threads, we don't need synchronization.
Let me design it as one block per dst with 128 threads. Block handles 4 dsts? No, one block per dst is simpler.
Wait, 640 blocks is fine. Let me check: with 132 SMs and 640 blocks, each SM gets ~5 blocks. With small blocks (e.g., 32 threads = 1 warp), each SM can run up to 32 blocks, so 5 is fine. But 1 warp per block is bad for occupancy since there's overhead.
Better: 64 threads per block, processing 2 dsts per block (32 threads per dst). Then we have 320 blocks, 2 warps each. Or 128 threads per block, 4 dsts per block.
Actually, for simplicity and maximum memory bandwidth, let me try:
- One block per dst
- 128 threads per block
- Each thread processes features: tid, tid+128, but since feat_dim=80, most threads do nothing
That's wasteful. We should match threads to work.
How about:
- One block per dst
- blockDim.x = 32 (one warp)
- Thread tid processes feature indices: tid, tid+32, tid+64 (if < 80)
- Threads 0-15: 3 features each (48 total)
- Threads 16-31: 2 features each (32 total)
- 48 + 32 = 80 ✓
Wait, 16*3 + 16*2 = 48 + 32 = 80. Yes!
But 1 warp per block means poor SM utilization due to block scheduling overhead. On modern GPUs, blocks of 128 threads are preferred.
Alternative: 128 threads per block, each block handles 4 dsts.
- Warp 0: dst 0
- Warp 1: dst 1
- Warp 2: dst 2
- Warp 3: dst 3
This is perfect: 640 dsts / 4 = 160 blocks. Each block has 4 warps = 128 threads.
160 blocks * 128 threads = 20480 threads total.
160 blocks / 132 SMs ≈ 1.2 blocks per SM. With block limit of 32 per SM, we could run many concurrently if we had more. But 160 blocks of 128 threads each should still keep the GPU reasonably busy since each warp has ~19 iterations of memory loads.
Actually, 160 blocks total means some SMs get 2 blocks and some get 1. That's not great. We need more blocks to saturate the GPU.
What about 2 threads per feature? That is, 64 threads per dst, processing 80 features. Each thread does 40/64... no, that's worse.
How about reducing feature assignment: 16 threads per dst, each handling 5 features?
- 16 threads * 5 features = 80 features
- Block of 128 threads handles 8 dsts (128/16 = 8)
- 640/8 = 80 blocks
- Even worse in terms of block count.
What about 1 thread per feature = 80 threads per dst?
- Block of 128 threads handles 1 dst with 80 threads active + 48 idle... bad
- Block of 256 threads handles 3 dsts (256/80 = 3 with 16 left over)... messy
Wait, I don't think block count is actually a huge problem here. 160 blocks of 128 threads each is 20,480 threads. But the kernel is entirely memory-bound. Let me think about memory bandwidth.
Actually, for memory bandwidth, we want:
1. Coalesced accesses
2. Enough concurrent memory transactions to saturate bandwidth
3. Good cache hit rate
The warp-per-dst design with 160 blocks (4 warps each) gives us coalesced accesses when loading features for the same src. But with only 160 blocks, there might not be enough concurrent warps to saturate bandwidth.
640 warps total. Each warp has ~19 memory iterations. At 3.35 TB/s, we need lots of concurrent memory requests.
What if we just have 1D grid with many blocks, where each thread handles one (dst, feat) pair?
- We can use e.g., 256 threads per block, and enough blocks to cover 51200 pairs
- 51200 / 256 = 200 blocks minimum
- Let's use 512 blocks * 256 threads = 131072 threads, each handling ~0.39 pairs on average
- Or 200 blocks is fine too, maybe launch more for better occupancy: e.g., 1024 blocks
The key question: what access pattern is better?
A) Threads in a warp work on same dst, different features (coalesced, broadcast src)
B) Threads in a warp work on different dsts, different features
Pattern A: When loading node_feat[src * 80 + feat], consecutive threads access consecutive floats (coalesced). And all threads use the same src (broadcast from cache). This is close to optimal.
Pattern B: When threads in a warp work on different dsts, each thread loads a different src. Some threads may load the same src by coincidence, but usually they're different. So we get up to 32 different src indices, leading to scattered accesses. However, consecutive threads DO access consecutive features, so within each src access it's coalesced. But each src access is a separate cache line.
Pattern A is clearly better for cache efficiency, especially since degrees are small and we iterate through neighbors.
So let me go with Pattern A but ensure we have enough blocks.
What if we use 32 threads per block (1 warp), with one block per dst? 640 blocks total.
- Each SM gets ~5 blocks
- 5 warps per SM is somewhat low for latency hiding, but H100 has very fast memory and good warp scheduling
- Actually, with 132 SMs and 640 blocks, it's ~4.8 warps per SM
- At 32 threads per warp, that's ~154 threads per SM
- H100 can have 2048 threads per SM, so we're at ~7.5% occupancy
- This might be too low for bandwidth saturation
What if we use 64 threads per block, 2 warps per block, with each warp handling one dst? Then 640/2 = 320 blocks.
- ~2.4 warps per SM
- Worse
What if we process 2 dsts per warp? 32 threads, each handling features for 2 dsts... that's messy because neighbor lists differ.
Let me think differently. What if we use a hybrid:
- Each block has 128 threads
- 32 threads (1 warp) handle dst = blockIdx.x * 4 + 0
- Another 32 handle dst = blockIdx.x * 4 + 1
- etc.
- 640 dsts / 4 = 160 blocks
- 4 warps per block
- Total warps: 640
- Warps per SM: ~640/132 ≈ 4.85
Alternatively, what if blocks are smaller? 64 threads = 2 warps, 2 dsts per block. 320 blocks, 640 warps total. Same total warps.
Actually, total warps is what matters for latency hiding, not blocks per se. With 640 warps total and 132 SMs, that's about 5 warps per SM. For H100, you generally want at least 10-20+ warps per SM to fully hide memory latency. But memory latency on H100 is much lower than older GPUs.
Hmm, let me think about whether we can increase warp count by having more than one warp per dst.
We can't really split a dst across multiple warps for this reduction efficiently (since max over a set needs communication, and the set is small anyway).
What about the transpose: process multiple feature dimensions per thread, but multiple threads handle the same feature?
Actually, what if we process the graph transposed? Instead of parallelizing over (dst, feat), we could parallelize over edges and features, then do an atomic max reduction. But atomic max over floats is slow, and with only 819k operations, the overhead might not be worth it.
Wait, what if we look at it differently. The total work is small (819k comparisons). The Python loop is slow because of Python overhead and lack of parallelism. A CUDA kernel with 640 warps might actually be fast enough to saturate memory bandwidth for this small dataset.
Let me compute memory bandwidth needed:
- Read row_ptr: 641 * 4 bytes = ~2.5 KB (negligible, cached)
- Read col_idx: 10240 * 4 bytes = ~40 KB
- Read node_feat (via gather): 10240 * 80 * 4 bytes = ~3.2 MB
- Write out: 640 * 80 * 4 bytes = ~204 KB
Total data movement: ~3.4 MB
At 3.35 TB/s, this takes ~1 microsecond in theory.
So the kernel should take roughly 1-5 microseconds. Python overhead dominates the reference.
For such a small problem, any reasonably written CUDA kernel should be much faster than the Python loop. The main challenge is just implementing it correctly.
Let me write a simple, correct kernel first and see if it's sufficient. I'll try the grid-stride 1D approach with enough threads, and also the warp-per-dst approach.
Actually, let me try a slightly more optimized version:
- 2D grid: (num_nodes, ceil(feat_dim / 32)) with 32 threads each
- Actually, each warp handles one dst, but we need 80 threads per dst... not ideal.
Let me try this:
- Grid = (num_nodes, (feat_dim + 31) / 32) = (640, 3)
- Block = (32, 1)
- Thread (dst, f_group, tid) handles feature = f_group * 32 + tid
- Features 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95 would be out of bounds for f_group=2, tid>=16
- So we need a bounds check
This gives us 640 * 3 = 1920 blocks. Each with 32 threads/1 warp.
Total warps = 1920. SMs get ~1920/132 ≈ 14.5 warps each. That's much better!
Total threads = 1920 * 32 = 61440, of which 640*80 = 51200 are active (83% utilization).
Memory access pattern:
- Threads in a warp (same dst, consecutive features within the 32-feature group)
- They access the same src (broadcast) and consecutive features (coalesced)
- This is excellent!
But wait, consecutive threads in x-dimension have consecutive tid, so for f_group=0, features 0-31 are consecutive floats. Coalesced! For f_group=1, features 32-63. Coalesced! For f_group=2, features 64-95, but only 64-79 are valid.
Yes, this is great!
Actually, I can improve further. 1920 blocks total. With 32 threads per block, not all threads in the last group of each dst do useful work. Specifically, in group 2, only threads 0-15 (16 threads) do work, threads 16-31 are idle.
I can use a 1D block of 128 threads and process multiple dsts and feature groups within the block. But that complicates the indexing. The 2D grid approach is clean.
Alternatively, I could make it even simpler:
- Grid = (num_nodes, 1)
- Block = 128 threads
- Each thread handles 1 feature, with some threads handling a 2nd feature
- Thread i handles features: i, i+128 if < 80... but 128 > 80, so thread i handles feature i if i < 80, else idle
- This means threads 80-127 are idle. That's 37.5% idle.
- 640 blocks * 128 threads = 81920 threads, 51200 active. Same total active threads.
- Warps per SM: 640*4 = 2560 warps / 132 ≈ 19.4. Very good!
- But 37.5% of threads are idle within each block. The warp scheduler still schedules all warps, but some threads in a warp are idle (specifically, threads 80-95 in the first 3 warps are idle? No wait, 128 threads = 4 warps. Warp 0: threads 0-31 all active. Warp 1: 32-63 all active. Warp 2: 64-79 active, 80-95 idle (half of warp active). Warp 3: 96-127 all idle.
Half-active warps and fully idle warps still consume scheduling resources. Not ideal.
The 2D grid approach (640, 3) with 32 threads each has:
- Block (dst, 0): all 32 threads active (features 0-31)
- Block (dst, 1): all 32 threads active (features 32-63)
- Block (dst, 2): threads 0-15 active, 16-31 inactive (features 64-79)
So each dst has 2.5 warps worth of active threads (2 full warps + 1 half warp). Equivalent to 80 threads per dst. The inactive portion for f_group=2 is only across 640 blocks. Total inactive threads: 640 * 16 = 10240 out of 61440 = 16.7% inactive. Better than 37.5%!
Let me refine the 2D grid approach. I can also use 16 threads for the last group:
- Grid = (640, 2) with blockDim=(32, 1)? No, then we only cover 64 features.
- Grid = (640, 2) with blockDim=(64, 1)? Then group 0 covers 0-63, group 1 covers 64-127 but only 64-79 valid. 44 out of 64 threads idle in group 1. Worse.
Actually, (640, 3) with 32 threads is probably fine. 16% thread waste is acceptable.
Or maybe: gridDim.x = num_nodes, blockDim.x = 80. But 80 is not a multiple of 32, so warps are split weirdly. And some SMs have limits on block size.
Let me try yet another option: process 2 dsts per block, 64 threads per block.
- 32 threads for dst_a, 32 threads for dst_b
- Total blocks: 320
- Each dst gets 2 full warps (both fully active since 32 threads cover 32 features, and each thread handles 2 or 3 features?)
Wait, 32 threads for 80 features: each thread handles 2-3 features. Let me refine:
- Thread tid in warp handles features: tid, tid+32, tid+64 (if < 80)
- Threads 0-15: 3 features
- Threads 16-31: 2 features
- All threads do useful work!
320 blocks * 64 threads = 20480 threads.
320 blocks * 2 warps = 640 warps total.
Warps per SM: 640/132 ≈ 4.85.
Hmm, back to the low warp count issue. But wait, in the previous (640, 3) 2D design, we had 1920 warps total. That's 4x more warps!
Actually, I just realized that in the (640, 3) design, consecutive feature accesses across the f_group boundary are not in the same warp. That is, features 31 and 32 are in different blocks. But that's fine because each feature is independent.
The memory access within a warp is coalesced because threads in a warp access consecutive features. Great.
But actually, we can get even more parallelism: what if we have multiple blocks per (dst, f_group) pair? No, that's unnecessary and would complicate the reduction.
Or: what if we process 1 feature per thread, but with smaller blocks?
- Grid = (num_nodes * feat_dim / 32, 1) with block size 32
- 51200 / 32 = 1600 blocks
- Total warps = 1600
- Warps per SM = ~12
But then threads in a warp may access different dsts, which means scattered src accesses. Let me think...
With 1600 blocks * 32 threads = 51200 threads total. Block 0: (dst=0, feat=0-31). Block 1: (dst=0, feat=32-63). Block 2: (dst=0, feat=64-79, with 16 threads idle). Block 3: (dst=1, feat=0-31). etc.
This is just flattening the 2D grid! Yes, equivalent to my 2D design but with linear block indexing:
- block_id linearized as blockIdx.x
- dst = block_id / 3 (if 3 feature groups)
- f_group = block_id % 3
Same thing.
OK, I think the (640, 3) 2D grid with 32 threads per block is a good design. Let me also consider using vectorized loads (float2, float4) to improve bandwidth.
With float4, each thread loads 4 features at once. For feat_dim=80, we'd need 20 float4s per neighbor. Block size = 20 threads? Then grid = (640, 1). Only 640 blocks of 20 threads each. That's 640*20 = 12800 threads, or 640*ceil(20/32) = 640 warps (since 20 threads = 1 warp with some idle). Warps per SM = ~4.85. And the memory pattern: 20 threads in a warp, all accessing float4 at the same src. First 20 threads coalesced, last 12 idle. This is worse in warp count.
What about block size = 80 threads, each loading float? Then 640 blocks. 80 threads = 2.5 warps per block (inefficient).
What about block = 32 threads, each loading float4? Then 640 blocks, each covering 128 features. But we only have 80 features. Wasteful and complicated.
I think scalar loads with the 2D grid are fine.
Let me also think about using shared memory to prefetch col_idx. Since max degree is ~19, we can load all col_idx for a dst into shared memory once, then all threads read from there. This avoids re-reading col_idx from global memory for each feature group.
With 3 feature groups per dst, each col_idx element is read 3 times from global memory in the naive approach. If we cache in shared memory, we read it once.
But col_idx is only 40 KB total, and L1 cache on H100 is quite large. The 3 reads might already be cached. But explicit shared memory prefetch could help.
Actually, with the 2D grid where each block handles one (dst, f_group), each block reads the same range of col_idx independently. So col_idx is read 3 times per dst, or 1920 times total for 640 dsts. But each block reads only its dst's col_idx. With 19 elements * 4 bytes = 76 bytes per read. L1 cache line is 128 bytes. So each read brings in ~2-3 col_idx elements into cache. But since blocks for the same dst run at different times, they might evict each other from L1.
Prefetching col_idx into shared memory for each block:
```cuda
__shared__ int s_col_idx[MAX_DEGREE];
int start = row_ptr[dst];
int end = row_ptr[dst + 1];
for (int i = threadIdx.x; i < end - start; i += blockDim.x) {
s_col_idx[i] = col_idx[start + i];
}
__syncthreads();
```
Then all threads read from s_col_idx. This is very fast for small degrees.
But wait, with blockDim=32 threads and max degree ~19, only 19 threads participate in the load, and the rest are idle during the loop. That's fine.
Actually, for block (dst, 0), we need col_idx[start:end]. For block (dst, 1), same. For block (dst, 2), same. If all three blocks run concurrently on different SMs, each loads the same data into its shared memory. That's redundant but not incorrect.
Let me implement this with shared memory prefetch. It should be very fast.
Here's the kernel design:
```cuda
__global__ void max_agg_kernel(
const int* row_ptr,
const int* col_idx,
const float* node_feat,
float* out,
int num_nodes,
int feat_dim
) {
int dst = blockIdx.x;
int feat_base = blockIdx.y * blockDim.x;
int feat = feat_base + threadIdx.x;
if (dst >= num_nodes) return;
int start = row_ptr[dst];
int end = row_ptr[dst + 1];
int degree = end - start;
__shared__ int s_col_idx[32]; // max degree is ~19, 32 is plenty
// Collaborative load of neighbor indices
for (int i = threadIdx.x; i < degree; i += blockDim.x) {
s_col_idx[i] = col_idx[start + i];
}
__syncthreads();
if (feat >= feat_dim) return;
float max_val = -INFINITY;
for (int e = 0; e < degree; e++) {
int src = s_col_idx[e];
float val = node_feat[src * feat_dim + feat];
max_val = fmaxf(max_val, val);
}
out[dst * feat_dim + feat] = max_val;
}
```
Grid: (640, 3, 1)
Block: (32, 1, 1)
Wait, I need to figure out the exact maximum degree. Let me check:
```python
degree = torch.full((num_nodes,), avg_degree, dtype=torch.int32)
degree = torch.clamp(degree + ((torch.arange(num_nodes, dtype=torch.int32) % 7) - 3), min=1)
```
avg_degree = 16
The term `(i % 7) - 3` ranges from -3 to 3.
So degree ranges from 13 to 19. Max is 19.
So shared memory of 32 int32 is definitely enough. Actually, 64 to be safe.
A potential issue: if blocks for the same dst are scheduled on the same SM, they share the L1 cache and compete for shared memory. But with only 640*3 = 1920 blocks total, and 132 SMs, it's about 14.5 blocks per SM. Each block uses only 64*4 = 256 bytes of shared memory. With 228 KB shared memory per SM, we can easily run all blocks concurrently if needed.
Let me also think about the case where degree = 0. In the reference:
```python
if end > start:
out[dst] = node_feat[col_idx[start:end].long()].amax(dim=0)
```
The degree is always >= 1 because of `min=1`. So degree is never 0. But the output is initialized to `-inf`, so for degree 0, output should remain `-inf`. Let me handle this in the kernel.
Actually, the degree is always >= 1 in get_inputs(). So we don't strictly need to handle degree=0. But let's be safe.
One more optimization: instead of each thread iterating through all neighbors and doing scattered loads, we could have the warp collaboratively load features into shared memory. But with degree<=19 and feat_dim=80, each warp loads 19*80=1520 floats=6KB. Shared memory per block is at most 48KB, but we use very little. We could have the warp load node_feat for all neighbors into a shared memory buffer, then threads read from there. But since the loads are coalesced anyway (same src, consecutive features), there's not much benefit - global memory bandwidth is already good for coalesced accesses.
Actually, there might be a benefit if we can exploit the fact that all threads in the block need the same src's features. Wait, in our design, each block handles one feature group (32 features) for one dst. So all threads in the block access the same set of src nodes, but at different feature offsets within a group. If we load the entire feature group for a src into shared memory, then subsequent accesses are from shared memory instead of global memory. But that requires 32 floats * 4 bytes = 128 bytes of shared memory per src. With degree 19, that's 19 * 128 = 2432 bytes. That's reasonable.
But the load pattern would be: for each src, 32 threads each load one float from global memory (the feature group). That's one coalesced 128-byte transaction. Then all future accesses (but there are no future accesses, each src is visited once) are from shared memory. Wait, in our kernel, each src is visited exactly once per block. So loading into shared memory first doesn't help - we still need to do the global memory load. The only difference is whether we store in shared memory and then read from there, or read directly into registers. Both require the same global memory transaction.
So shared memory for node_feat doesn't help. Shared memory for col_idx does help because col_idx is reused across all threads in the block (32 threads each access all 19 col_idx elements). Without shared memory, each thread reads col_idx from global memory or L1 cache. With 32 threads, the first few threads might get cache misses, and subsequent threads get cache hits if they run close enough in time. But with warp execution, threads in a warp execute simultaneously, so they all access col_idx[0] at the same time. That means 32 simultaneous accesses to the same 4-byte word, which becomes one broadcast from L1 cache. Same for col_idx[1], etc. So even without shared memory, the col_idx accesses might be efficiently broadcast.
But loading col_idx into shared memory explicitly ensures that we read it once from global memory (via the first warp or a subset of threads), then all threads read from shared memory with no bank conflicts (since all threads read the same address simultaneously, which is broadcast). This is slightly better.
Let me include the shared memory optimization for col_idx.
One more thing: should we tune the number of feature groups? With feat_dim=80 and blockDim=32, we have 3 groups with the last one half-empty. We could use blockDim=16:
- 80/16 = 5 groups exactly
- Grid = (640, 5)
- Total blocks = 3200
- Total warps = 3200
- Warps per SM = ~24
- All threads active in all blocks! No waste!
But with blockDim=16, consecutive threads access 16 consecutive floats. That's still coalesced (one 64-byte transaction per warp). And all threads in all warps are active. This is better!
Wait, a warp has 32 threads. With blockDim=16, each block has 1 warp but only 16 threads are active. Actually... no. CUDA always executes in warps of 32. If blockDim.x = 16, CUDA still issues a warp of 32 threads, but thread 16-31 have threadIdx.x >= blockDim.x, so they are "out of bounds" in our code. But they still execute! We need to make sure our bounds check handles this.
In my kernel:
```cuda
int feat = feat_base + threadIdx.x;
if (feat >= feat_dim) return;
```
If blockDim.x = 16, then for feat_base = 64, threadIdx.x ranges 0-15, feat ranges 64-79. All valid. But CUDA issues one warp of 32 threads where threadIdx.x is 0-15 (valid) and 16-31 (would have threadIdx.x >= blockDim.x so the hardware handles this? Actually, no, blockDim.x=16 means block has 16 threads, so CUDA should only issue one warp per block, but I'm not sure if that warp has all 32 threads active or only 16).
Wait, I need to be more careful. In CUDA, the warp size is always 32. A block of 16 threads forms one warp, but only the first 16 threads are "active". Thread indices 16-31 don't exist in that block - they would be out of bounds if accessed. So if I have a block of 16 threads, there's exactly one warp with 16 active threads.
Let me confirm: a block size of 16 means 16 threads total. These 16 threads form one warp (they occupy lanes 0-15 of the warp, lanes 16-31 are inactive). So there are no threadIdx.x values of 16 or higher in the block.
So with blockDim=16 and grid=(640, 5):
- Block (dst, 0): threads 0-15 handle features 0-15. All 16 threads active.
- Block (dst, 1): threads 0-15 handle features 16-31. All 16 active.
- Block (dst, 2): features 32-47. All active.
- Block (dst, 3): features 48-63. All active.
- Block (dst, 4): features 64-79. All active.
Total: 640 * 5 = 3200 blocks, each with 16 threads = 1 warp.
Total warps = 3200.
Warps per SM = 3200/132 ≈ 24.2.
This is excellent! 24 warps per SM is great for latency hiding. And there are no idle threads.
But is 16-thread coalescing good enough? Coalescing happens at warp level. A warp of 16 threads accessing 16 consecutive floats = 64 bytes. This fits in one or two 32-byte transactions, which is very efficient. With L1 cache, 64 bytes is one cache line. Perfect.
And all threads in the warp access the same src (broadcast from cache), at consecutive features. The global memory loads are perfectly coalesced.
This is probably the sweet spot!
Wait, but let me think about whether block size 16 is allowed/supported. Yes, CUDA supports blocks as small as 1 thread. There's overhead per block, but with 3200 blocks, it's fine.
Let me double check: H100 has 132 SMs. Maximum concurrent blocks per SM is 32. So total max concurrent blocks = 132 * 32 = 4224. We have 3200 blocks, which is less than 4224. Good, all blocks can potentially run concurrently.
But wait, each block only has 16 threads, and max threads per SM is 2048. So max concurrent blocks per SM is min(32, 2048/16) = 32. Total concurrent blocks = 4224. But we only have 3200 blocks. So there will be SMs with fewer blocks. Actually, 3200 blocks / 132 SMs = about 24 blocks per SM on average. Since each SM can run 32 blocks of 16 threads (512 threads), we'd be at 24*16 = 384 threads per SM. That's 18.75% occupancy, which is somewhat low.
Hmm, 384 threads per SM means 12 warps. Actually wait, 24 blocks of 16 threads = 24 warps per SM? No, each block of 16 threads is 1 warp. So 24 blocks = 24 warps. At 32 threads per warp... but 16-thread blocks have 16 active threads per warp. The occupancy is limited by warp count, not thread count.
Actually, CUDA occupancy is often measured in warps. With 24 warps per SM and a maximum of 64 warps per SM (on some architectures), that's 37.5% warp occupancy. H100 might support more warps per SM. Let me check: H100 has 64 warps per SM maximum (2048 threads / 32 = 64). So 24/64 = 37.5% occupancy.
37.5% occupancy is decent, especially for a memory-bound kernel. But can we do better?
If we use blockDim=32 (1 warp of 32 threads):
- 80/32 = 2.5, so we need 3 feature groups.
- Grid = (640, 3)
- Blocks = 1920
- Warps = 1920
- Warps per SM = 1920/132 ≈ 14.5
- Occupancy = 14.5/64 ≈ 22.7%
- But 16.7% of threads are inactive.
Hmm, 24 warps per SM (blockDim=16) vs 14.5 warps per SM (blockDim=32). More warps is generally better for latency hiding. But blockDim=32 has more threads per block, which might reduce block scheduling overhead.
Wait, actually with blockDim=16, we have 3200 blocks, and 3200 warps. With blockDim=32, we have 1920 blocks and 1920 warps.
3200 warps / 132 SMs = 24.2 warps per SM.
1920 warps / 132 SMs = 14.5 warps per SM.
24.2 is better. And each warp with blockDim=16 has all 16 threads active, whereas with blockDim=32, the last group has only 16 active threads.
But wait, I said each block of 16 threads is 1 warp. Is that right? Yes, 16 threads form one warp (occupying lanes 0-15, lanes 16-31 inactive).
Actually, I just realized something important. With 3200 blocks and max 32 blocks per SM, if each SM runs 32 blocks concurrently, that's 32*16 = 512 threads per SM. With maximum 2048 threads per SM, we can run 128 blocks if block size is 16. But the hardware limit is 32 blocks per SM. So we're limited to 32 blocks = 512 threads = 16 warps (where each warp has 16 active threads, but the warp still counts as a warp). Wait, no, each block of 16 threads is one warp. So 32 blocks = 32 warps.
Actually, let me be more precise. On H100:
- Max blocks per SM: 32
- Max threads per SM: 2048
- Max warps per SM: 64
A block of 16 threads = 1 warp (with 16 active threads).
Max concurrent blocks of 16 threads per SM = min(32, 2048/16) = min(32, 128) = 32.
Max concurrent warps = 32.
Occupancy = 32/64 = 50%.
A block of 32 threads = 1 warp.
Max concurrent blocks = min(32, 2048/32) = min(32, 64) = 32.
Max concurrent warps = 32.
Occupancy = 32/64 = 50%.
Wait, both give 50% max occupancy per SM! But blockDim=16 gives 3200 blocks total, so all 3200 can run across SMs. With 132 SMs * 32 blocks = 4224 max concurrent blocks, and we have 3200, so all can run at once.
For blockDim=32, we have 1920 blocks total, which also fits within 4224.
But with blockDim=16, 3200 blocks / 132 SMs = 24.2 average blocks per SM at full distribution. Since each SM can run 32 blocks, that's 75.7% block utilization. Each SM has 24.2 warps * 16 threads = 387 threads. At 24.2 warps per SM, that's 37.8% warp occupancy.
For blockDim=32, 1920 / 132 = 14.5 blocks per SM. 14.5 / 32 = 45.3% block utilization. 14.5 warps per SM = 22.7% warp occupancy.
So blockDim=16 actually gives better occupancy in terms of warp count! 24.2 vs 14.5.
OK, I'm overthinking this. For such a small problem, either approach will be very fast. Let me just pick one and implement it.
Actually, I think blockDim=32 is simpler and the slight reduction in warp count shouldn't matter much. The memory access pattern is still excellent. Let me go with blockDim=32, grid=(640, 3).
Wait, another idea: what if I use block size 64 or 128 and have the block process multiple feature groups for one dst? Like 128 threads processing all 80 features of one dst, where each thread handles some features.
Block size 128:
- Threads 0-79 handle one feature each
- Threads 80-127 idle
- 640 blocks
- 640 warps total (5 warps per block)
- Warps per SM: 640*5/132 = 24.2
- But 37.5% of threads are idle
With 24.2 warps per SM and coalesced accesses, this might actually work well. But having idle threads in warps is annoying.
What about 80 threads per block?
- Each thread handles 1 feature
- 640 blocks
- 640 * ceil(80/32) = 640 * 3 = 1920 warps? Wait, 80 threads = 3 warps (2.5 warps, but rounded up to 3 warps: 0-31, 32-63, 64-79 in 3rd warp with 16 active threads).
- Total warps = 1920
- Warps per SM = 1920/132 = 14.5
- 16.7% thread waste (in the 3rd warp)
This is very similar to the blockDim=32, grid=(640, 3) case, except the threads for a dst are all in one block instead of spread across 3 blocks. The total active threads and total warps are the same.
Actually, having all feature groups for a dst in the same block means we only need to load col_idx once per block instead of 3 times (once per feature group). This is a significant advantage!
With 80 threads per block, one block per dst:
- Load col_idx into shared memory (collaborative, all 80 threads participate, but only 80 threads = 2.5 warps)
- All 80 threads then iterate through neighbors independently
- Each dst's col_idx is loaded exactly once
With grid=(640, 3) and blockDim=32:
- Each of the 3 blocks for a dst loads col_idx independently
- Total col_idx loads = 3 * 640 = 1920
- With caching, maybe only the first load misses and the next two hit? But blocks for the same dst might run far apart in time.
- More redundant global memory reads.
So the 80-threads-per-block approach might be better due to shared col_idx caching.
But wait, can we even use 80 threads per block? Yes. And CUDA will execute it as 3 warps. With 1920 total warps across 132 SMs = ~14.5 warps per SM. That's decent.
Let me compute shared memory for col_idx prefetch with 80 threads:
```cuda
__shared__ int s_col_idx[32]; // small
int degree = end - start;
for (int i = threadIdx.x; i < degree; i += blockDim.x) {
s_col_idx[i] = col_idx[start + i];
}
__syncthreads();
```
With blockDim=80 and degree<=19, the loop runs once (threadIdx.x < 19 loads, threads 19-79 skip). Then __syncthreads().
This is very efficient. Let me go with 80 threads per block, 640 blocks.
Actually, I want to double check: are 80 threads per block allowed? Yes, any number from 1 to 1024 is valid (for 1D blocks).
And the grid: just 640 blocks in x-dimension. Simple.
Kernel:
```cuda
__global__ void max_agg_kernel(
const int32_t* row_ptr,
const int32_t* col_idx,
const float* node_feat,
float* out,
int num_nodes,
int feat_dim
) {
int dst = blockIdx.x;
int feat = threadIdx.x;
if (dst >= num_nodes || feat >= feat_dim) return;
int start = row_ptr[dst];
int end = row_ptr[dst + 1];
int degree = end - start;
if (degree == 0) {
out[dst * feat_dim + feat] = -INFINITY;
return;
}
__shared__ int s_col_idx[32];
for (int i = threadIdx.x; i < degree; i += blockDim.x) {
s_col_idx[i] = col_idx[start + i];
}
__syncthreads();
float max_val = -INFINITY;
for (int e = 0; e < degree; e++) {
int src = s_col_idx[e];
float val = node_feat[src * feat_dim + feat];
max_val = fmaxf(max_val, val);
}
out[dst * feat_dim + feat] = max_val;
}
```
Wait, `threadIdx.x` might be >= degree and < blockDim.x. In the shared memory load loop, those threads don't participate. That's fine.
But there's a subtle issue: `__syncthreads()` requires all threads in the block to reach it. Since we have `if (dst >= num_nodes || feat >= feat_dim) return;` at the top, if some threads in a warp hit this return and others don't, we get divergence but all threads in the block still eventually reach `__syncthreads()`... wait, no. If a thread returns early, it never reaches `__syncthreads()`, causing deadlock.
In our case:
- `dst = blockIdx.x`, all threads in a block have the same `dst`.
- `feat = threadIdx.x`, and `feat_dim = 80`, `blockDim.x = 80` (or whatever).
- If blockDim.x > feat_dim, some threads have feat >= feat_dim and would return early.
So if I use blockDim=80, no thread has feat >= 80, so no early return. Great.
If I used blockDim=128, threads 80-127 would return early and never reach __syncthreads(). Deadlock.
So with blockDim=80, we're safe.
But I also need to handle `dst >= num_nodes`. With 640 blocks (blockIdx.x = 0..639) and num_nodes = 640, no block has dst >= num_nodes. Safe.
So blockDim=80 is safe for our specific case.
But to make it general, if we launch exactly `num_nodes` blocks with `feat_dim` threads each, there are no out-of-bounds threads in the block. Good.
However, I realize that if `feat_dim` is not 80 but something else, this might not be the optimal block size. But for this problem, it is.
Actually, I just realized that 80 is not a multiple of 32. The warp execution is:
- Warp 0: threads 0-31 (all active)
- Warp 1: threads 32-63 (all active)
- Warp 2: threads 64-79 (active), threads 80-95 don't exist
Wait, blockDim.x = 80 means exactly 80 threads. These form 3 warps? No, 80/32 = 2.5. So:
- Warp 0: threads 0-31 (32 threads)
- Warp 1: threads 32-63 (32 threads)
- Warp 2: threads 64-79 (16 threads), plus threads 80-95 don't exist
In CUDA, warp 2 still has 32 lanes, but only lanes 0-15 (corresponding to threads 64-79) are active. Lanes 16-31 are inactive. This is fine.
The `__syncthreads()` is called by all 80 threads. Since all active threads reach it, it's fine.
Let me also consider whether we can use a smaller block to increase block count and thus occupancy. We can't change block count because block count = num_nodes = 640. With blockDim=80, that's fixed.
What if we process multiple dsts per block? Say 2 dsts per block with 80 threads each... that would need 160 threads. Or 4 dsts per block with 40 threads each... let's think.
If we use 40 threads per dst and process 2 dsts per block (80 threads total):
- For each dst, 40 threads cover 80 features (2 features per thread)
- 640 dsts / 2 = 320 blocks
- 320 blocks of 80 threads each
- Total warps = 320 * ceil(80/32) = 320 * 3 = 960 warps
- Warps per SM = 960/132 ≈ 7.3
Worse than 1920 warps with the single-dst-per-block design.
What if we process 1 dst per block but use fewer threads per dst? Say 20 threads per dst, each handling 4 features.
- Block = 20 threads
- 640 blocks
- Total warps = 640
- Warps per SM = 640/132 ≈ 4.85
- Even worse.
What if we process 2 dsts per block, 64 threads per dst? 128 threads per block.
- Each thread handles 1 or 2 features
- 320 blocks
- 320 * 4 = 1280 warps
- Warps per SM = 9.7
- Still worse.
So 80 threads per dst, 640 blocks, 1920 warps seems like the best balance for this problem.
Actually, let me reconsider the 2D grid (640, 3) with 32 threads per block. Total blocks = 1920. Each block has 1 warp of 32 threads. Total warps = 1920. Same total warps! But col_idx is loaded 3 times per dst.
Hmm, is there a way to get more warps? Only by having more blocks or larger blocks (more warps per block). With 640 dsts, the max blocks is unbounded in principle, but practically we want one logical unit (dst or feature group) per block.
What if we use 16 threads per block and 5 feature groups? Grid = (640, 5). Blocks = 3200. Warps = 3200. Warps per SM = 24.2. Much better!
And each block loads col_idx once. Total col_idx loads = 3200. But blocks for the same dst load the same col_idx 5 times. Same redundancy as the (640, 3) case with 32 threads.
Wait, with 80 threads in one block per dst, col_idx is loaded once. With 3200 blocks (16 threads each, 5 per dst), col_idx is loaded 5 times. So there's a tradeoff: fewer loads vs more warps.
For a memory-bound kernel, more warps is usually better. But col_idx is tiny (40 KB total, 76 bytes per dst). Reading it 5 times instead of once is only 380 bytes per dst, or 240 KB total. That's negligible compared to node_feat bandwidth (3.2 MB). So the extra col_idx reads don't matter.
But the 3200-block design has 16 threads per block = 1 warp with 16 active threads. The warp still counts as one warp. And 3200 warps total gives better latency hiding.
However, there might be higher block scheduling overhead with 3200 blocks compared to 640 blocks. But 3200 blocks is still not that many.
Let me actually try both approaches and see which is faster! I can write the kernel and test it.
Actually, let me just implement a simple, clean kernel first and then optimize based on profiling. I'll start with the 1D block size 80 approach because it's simple and elegant.
Let me write the code.
One more thing: I should check if there are any issues with `-INFINITY`. In CUDA, we can use `-CUDART_INF_F` or `-INFINITY` (from math.h) or `__int_as_float(0xff800000)`. Let me just use `-INFINITY` which should work with `#include <math.h>` or it's a built-in in CUDA.
Actually, in CUDA C, `INFINITY` is defined in `math.h` or `cmath`. I'll include `<float.h>` or `<math.h>`.
Wait, for float values, I can also initialize with `-3.402823466e+38f` or just use `fmaxf` starting from `node_feat[col_idx[start] * feat_dim + feat]` as the initial value.
Let me rewrite:
```cuda
float max_val = node_feat[s_col_idx[0] * feat_dim + feat];
for (int e = 1; e < degree; e++) {
int src = s_col_idx[e];
float val = node_feat[src * feat_dim + feat];
max_val = fmaxf(max_val, val);
}
```
But what if degree == 0? The reference uses `-inf` as the default. In our case, degree >= 1, but let me handle it properly:
```cuda
float max_val = -INFINITY;
for (int e = 0; e < degree; e++) {
...
}
```
I'll use `-INFINITY`.
Let's write the full Python file.