reasoning
Let me analyze the task carefully.
The reference model does:
1. ConvTranspose2d (in_channels=64, out_channels=64, kernel_size=3, stride=2, padding=1, output_padding=1)
2. Mish activation
3. Add 0.5
4. Hardtanh (min=-1, max=1)
5. Scale by 2
Input shape: [128, 64, 128, 128]
Output shape after conv_transpose: needs calculation.
For ConvTranspose2d:
Output size = (input_size - 1) * stride - 2 * padding + kernel_size + output_padding
For H=W=128:
(128 - 1) * 2 - 2 * 1 + 3 + 1 = 127 * 2 - 2 + 3 + 1 = 254 + 2 = 256
So output shapes: [128, 64, 256, 256]
This is a fairly large operation. Let me think about how to optimize it.
The main operations are:
1. ConvTranspose2d - this is the heavy compute operation
2. Elementwise ops: Mish, add, hardtanh, scale
Mish = x * tanh(softplus(x)) = x * tanh(ln(1 + exp(x)))
Since we have a sequence of conv transpose followed by elementwise ops, we can potentially fuse the elementwise ops into the conv transpose output write, saving memory bandwidth.
However, implementing a full conv transpose kernel from scratch is very complex. Let me think about what PyTorch does under the hood.
For ConvTranspose2d with stride > 1, PyTorch typically implements it as:
1. An upsampling (insert zeros) + convolution, OR
2. A specialized deconvolution kernel
On H100 with cuDNN, the transposed convolution will likely use highly optimized implicit GEMM algorithms. Fusing elementwise operations with cuDNN deconv is not straightforward.
One approach: we can try to use torch.nn.functional.conv_transpose2d and then fuse the elementwise ops ourselves.
Actually, maybe we can do better by writing a custom kernel that does the elementwise fusion while leveraging PyTorch's conv_transpose2d. But the reference already does that, and the elementwise ops are cheap.
Wait - can we implement the conv transpose using an explicit col2im approach, or perhaps use grouped conv? Let me think.
Actually, for a more significant speedup, we could try to:
1. Use implicit GEMM style kernel for deconv
2. Fuse all the pointwise operations
But implementing a full optimized ConvTranspose2d is very hard. Let me see if there's a simpler approach.
For deconv with stride=2, kernel=3, we can think of it as:
- The input [128, 64, 128, 128] gets expanded to [128, 64, 256, 256]
- This is equivalent to: for each output pixel, it's a weighted sum of neighboring input pixels based on the kernel
Actually, we could transpose the problem. ConvTranspose2d(kernel=3, stride=2, padding=1, output_padding=1) from 64 to 64 channels is equivalent to:
- For each input pixel, it contributes to a 3x3 region in the output (with stride 2)
We could implement this as a custom CUDA kernel where each thread computes one output pixel (or one tile of output pixels), and fuses the elementwise ops. This would avoid writing intermediate results to global memory and loading them back.
But the arithmetic intensity of deconv is relatively low. Let me calculate:
- Input size: 128 * 64 * 128 * 128 = ~134M elements
- Output size: 128 * 64 * 256 * 256 = ~536M elements
- Kernel: 64 * 64 * 3 * 3 = ~36K params
For each output pixel, we need to compute a 64-dim vector. Each output position is computed from at most ceil(3/2)^2 = 4 input positions (since stride=2).
Actually, for ConvTranspose2d:
Each output position (c_out, h, w) is computed as a sum over c_in and kernel positions (kh, kw):
out[c_out, h, w] += weight[c_in, c_out, kh, kw] * inp[c_in, h', w']
where h', w' are determined by the deconv mapping.
For stride=2, kernel=3, padding=1, output_padding=1:
The inverse formula: h' = floor((h + padding - kh) / stride)
For each output position, there might be 0 or 1 corresponding input positions for each (kh, kw), but more precisely, each output position gets contributions from up to a few input positions.
Actually, for deconvolution:
out[n, c_out, h, w] = sum_{c_in} sum_{kh, kw} weight[c_in, c_out, kh, kw] * in[n, c_in, (h + padding - kh) / stride, (w + padding - kw) / stride]
where the division is valid only when (h + padding - kh) % stride == 0.
Since stride=2, for each output position (h, w), among the 9 kernel positions, only those where (h + 1 - kh) is even AND (w + 1 - kw) is even contribute. That means for each output position, at most ceil(9/4) = but more precisely about 2-3 kernel positions contribute per input channel... actually no.
Wait. Let me reconsider. For a given output position (h, w), we check each (kh, kw):
h_in = (h + 1 - kh) / 2, which must be integer and in [0, 127]
w_in = (w + 1 - kw) / 2, which must be integer and in [0, 127]
For h in [0, 255], h+1 in [1, 256], kh in [0, 2]:
- h+1-kh ranges from -1 to 256. Even values in this range that are in [0, 254] are valid.
- For a given h, at most 2 values of kh make h+1-kh even? Let's check:
If h+1 is even, kh even (0, 2) -> 2 options
If h+1 is odd, kh odd (1) -> 1 option
So for each output pixel, the number of kernel positions that contribute is 1, 2, or 4. On average, about (1/4)*1 + (1/2)*2 + (1/4)*4 = 2.25 kernel positions per (c_in, c_out) pair? No, actually independent in h and w.
For h: on average (0.5*2 + 0.5*1) = 1.5 valid kh
For w: on average 1.5 valid kw
Total: ~2.25 valid (kh, kw) pairs per output pixel.
So each output element requires ~2.25 * 64 * 64 = ~9216 multiplies.
Total output elements: 128 * 64 * 256 * 256 = 536,870,912
Total FLOPs: ~536M * 9216 = ~4.9T FLOPs? That seems too high. Let me recalculate.
Wait, each output element is a vector of 64 channels. So for each output position (batch, h, w), we compute 64 channels. Each channel requires ~2.25 * 64 multiplies-adds.
So per output position: 64 * 2.25 * 64 = 9216 ops.
Total: ~536M positions? No, positions = 128 * 256 * 256 = 8,388,608.
Total FLOPs = 8.4M * 9216 = ~77.3B FLOPs.
At 67 TFLOPS, this would take ~1.15ms if compute bound. But memory bandwidth is 3.35 TB/s.
If we use PyTorch's conv_transpose2d, it likely uses cuDNN which is very optimized. Fusing elementwise ops might give us a small win since we save reading/writing the output once.
But wait - on H100, with TF32 tensor cores at ~500 TFLOPS (without sparsity), 77B FLOPs would take ~0.15ms. The kernel is likely memory bandwidth bound since the implicit GEMM approach has to load the weight matrix.
Actually, for ConvTranspose2d, cuDNN might implement it using:
1. im2col + GEMM, or
2. Direct convolution, or
3. FFT-based approach
If we fuse the elementwise ops into the output writeback of the GEMM, we save one read and one write of the output tensor. The output tensor is 536M elements * 4 bytes = 2.14 GB. Saving 2.14 GB of memory traffic at 3.35 TB/s saves ~0.64ms. But if the overall kernel is memory bound, the actual savings depend.
But can we actually write a custom deconv kernel that's faster than cuDNN? That's very hard.
Another approach: use CUTLASS or some template. But writing a custom implicit GEMM for deconv is extremely complex.
Wait - maybe PyTorch's reference isn't that optimized because:
1. It uses conv_transpose2d from PyTorch
2. Then mish (which creates a temp)
3. Then add (temp)
4. Then hardtanh (temp)
5. Then multiply (temp)
If we replace the sequence of elementwise ops with a fused kernel after conv_transpose2d, we'd save memory bandwidth for the intermediate activations.
Actually, looking more carefully: the scale is 2, add_value is 0.5.
We could do:
x = self.conv_transpose(x)
return fused_mish_add_hardtanh_scale(x, 0.5, 2.0)
This would save 3 reads/writes of x. The tensor is 2.14 GB. Saving ~6.4 GB of memory bandwidth. At 3.35 TB/s that's 1.9ms.
But cuDNN conv_transpose2d is probably quite fast. Let me think about what the reference performance might be.
Actually, maybe the better approach is to try to fuse the pointwise ops with the conv_transpose using a custom kernel wrapper, or just write a fused pointwise kernel.
But is there an even better approach? What about using CUTLASS to implement a more efficient deconv? Probably too complex.
Let me try a simpler approach first: since the stride=2, maybe we can implement the deconvolution ourselves using a direct approach where each thread computes output pixels, and we fuse the activations. If we can achieve good occupancy and avoid global memory intermediates, we might beat cuDNN for this specific small-kernel case, since cuDNN's overhead might be higher for this configuration.
Actually, another idea: ConvTranspose2d(stride=2, kernel=3, padding=1, output_padding=1) on a 128x128 input producing 256x256 output is basically a 2x upsampling with a learned 3x3 filter. We could express this differently:
- Use nn.PixelShuffle or interpolate, then conv? No, that's not equivalent.
Actually, deconvolution with stride 2 can be written as:
- Each input channel contributes to a 3x3 patch in the output with offsets determined by stride
- Because output_padding=1, (128-1)*2 - 2*1 + 3 + 1 = 256, yes.
For a direct kernel: we could have each thread block compute a tile of output (e.g., 16x16 pixels across all 64 channels for a subset of the batch). Each output pixel requires reading at most 2x2=4 input pixels per input channel? Wait, no.
Let me think more carefully about the direct deconv implementation.
In transposed convolution, each input pixel "spreads" to a kernel-sized patch in the output. For stride=2, kernel=3:
- Input pixel at (h_in, w_in) contributes to output at positions:
(h_out, w_out) where h_out = h_in * 2 - 1 + kh, w_out = w_in * 2 - 1 + kw
for kh in [0, 2], kw in [0, 2]
But with padding=1, the formula is:
h_out = (h_in) * stride - padding + kh = h_in * 2 - 1 + kh
Wait, standard formula for ConvTranspose2d:
H_out = (H_in - 1) * stride - 2*padding + kernel_size + output_padding
= (H_in - 1) * stride - 2*padding + dilation*(kernel_size-1) + output_padding + 1
More commonly, for each input position, it maps to a set of output positions.
Actually, for the forward pass of ConvTranspose2d, PyTorch computes:
output_size = (input_size - 1) * stride - 2*padding + kernel_size + output_padding
And conceptually it can be viewed as convolving a dilated input (zeros inserted) with the transposed weight.
If dilation=1:
- Insert stride-1 = 1 zero between each input pixel
- Apply padding of (kernel_size - padding - 1) = (3 - 1 - 1) = 1?
Actually, the equivalent conv has:
- Padding = kernel_size - 1 - padding = 2 - 1 = 1? No...
For ConvTranspose2d:
Equivalent conv parameters:
stride = 1
dilation = 1 in the weight, but between input elements there are stride-1 zeros
padding = kernel_size - 1 - padding = 3 - 1 - 1 = 1
Wait, I'm confusing myself. Let me use the standard result:
A ConvTranspose2d with kernel_size=k, stride=s, padding=p, output_padding=out_p is equivalent to:
1. Take input of size H
2. Insert s-1 zeros between each row/column -> size H' = H + (H-1)*(s-1) = H*s - s + 1
3. Pad with (k - p - 1) on each side -> size H'' = H' + 2*(k-p-1)
4. Convolve with kernel size k, stride 1, padding 0 -> output size = H'' - k + 1
5. Crop additional out_p pixels somehow? Or add out_p padding...
Actually the formula gives: (H-1)*s - 2*p + k + out_p
With H=128, s=2, p=1, k=3, out_p=1: 127*2 - 2 + 3 + 1 = 256
With my equivalent formulation:
H' = 128 + 127 = 255
Pad with (3-1-1) = 1 on each side: H'' = 255 + 2 = 257
Conv with k=3, stride=1, pad=0: output = 257 - 3 + 1 = 255
With output_padding=1: 255 + 1 = 256. Yes, so we need to add output_padding additional zeros at the end (or right/bottom).
So conceptually: dilated input is 255x255, pad to 257x257, conv with stride 1 to get 255x255, then add 1 more row/column of zeros (or just expand by 1). The effective "receptive field" per output pixel is small.
For a direct CUDA kernel, each output pixel (h, w) corresponds to:
- In the dilated image of size 255x255, after padding by 1 on each side, we have size 257x257.
- The output of valid conv is 255x255.
- Then we add output_padding to get 256x256.
Actually, it's cleaner to just implement the inverse mapping directly:
For each output position (h, w), find which input positions and kernel weights contribute.
Standard transposed convolution:
out[n, c_out, h, w] = sum_{c_in} sum_{kh=0}^{2} sum_{kw=0}^{2}
weight[c_in, c_out, kh, kw] * in[n, c_in, h', w']
where h' and w' satisfy:
h = h' * stride - padding + kh (in the standard formulation, but this varies)
Actually, the exact formula for PyTorch's ConvTranspose2d is:
h = (h' * stride) + kh - padding
Wait, with output_padding, there's: h = (h' * stride) + kh - padding, and then the output might be extended.
Let me check: for h'=0, kh=0: h = 0 + 0 - 1 = -1. But padding is typically handled by only considering valid regions.
Actually, PyTorch handles padding by cropping the output. The actual formula used inside the kernel might differ.
Let me think about it differently. Instead of trying to outperform cuDNN on the deconv itself (which is extremely hard), let's try to:
1. Use PyTorch's conv_transpose2d for the heavy lifting
2. Fuse all the elementwise ops into a single kernel
For even more speedup, maybe we can pre-process the weights or use a different layout.
Wait, another idea: can we express the hardtanh + scale as a single operation?
hardtanh(x, -1, 1) * 2
= min(max(x, -1), 1) * 2
= min(max(x*2, -2), 2)
And x + 0.5 followed by hardtanh and scale:
hardtanh(mish(y) + 0.5, -1, 1) * 2
= min(max(mish(y) + 0.5, -1), 1) * 2
= min(max(mish(y)*2 + 1, -2), 2)
But mish is nonlinear so we can't simplify much.
Fusion of elementwise ops after conv_transpose is the most practical approach.
However, I wonder if we can do better by implementing a simple direct deconv kernel that's fused with the elementwise ops. Since the kernel is only 3x3 and stride is 2, the computation per output pixel is very structured.
For each output pixel, there are at most 2.25 weight-input pairs per channel, so about 2.25 * 64 * 64 = 9216 multiplications per output pixel (for all 64 output channels). Actually, wait - for a single output channel, it's sum over c_in and valid (kh, kw), so about 2.25 * 64 = 144 multiplications per output channel per pixel. For 64 output channels: 9216 ops.
Total output pixels: 128 * 256 * 256 = 8,388,608 pixels.
Total output channels to compute: 128 * 64 * 256 * 256 = 536,870,912.
If we have each thread compute one output channel element:
Total threads = 536.9M
At full occupancy (~2000 threads per SM, ~132 SMs), we have ~264K concurrent threads. Each thread does ~144 multiplications.
This is actually very feasible!
And since we're reading input elements and weights, let's check memory:
- Input: 128 * 64 * 128 * 128 * 4B = 512 MB
- Weights: 64 * 64 * 3 * 3 * 4B = 144 KB
- Output: 128 * 64 * 256 * 256 * 4B = 2 GB
Each input element is read multiple times. Specifically, each input pixel at (n, c_in, h, w) contributes to up to 9 output positions (3x3 kernel) per output channel. So each input element is read ~9 * 64 = 576 times if not cached. That's a lot of re-reading. But the weights are only 144KB so they fit in L2 cache nicely.
Actually, wait. In direct deconv, each input element contributes to an output patch. But when we iterate over output positions (each thread computing one output element), the memory reads are:
- For each output element: read the corresponding input elements (up to 2.25 per c_in) and weights.
So total input reads: ~536.9M * 2.25 * 64 = 77B reads. That's 308 GB of input reads!
Total weight reads: similarly large.
This is terrible for memory bandwidth! That's why direct convolution is usually not used for large channels - GEMM-based approaches are much better because they reuse data through shared memory.
So implementing direct deconv for 64 input and output channels is probably not going to beat cuDNN which uses sophisticated GEMM or Winograd algorithms.
Therefore, the best practical approach is:
1. Use PyTorch's conv_transpose2d (which calls cuDNN)
2. Fuse all the elementwise operations into a single custom CUDA kernel
Let me write a fused elementwise kernel and see what speedup we get.
Actually, looking at the reference more carefully, PyTorch might already fuse some operations through its JIT or eager mode optimizations. But mish, add, hardtanh, multiply are separate kernels in eager mode.
Let me count the memory operations in the reference:
1. conv_transpose2d: reads input (512MB), reads weights (144KB), writes output (2GB)
2. mish: reads output (2GB), writes output (2GB)
3. add: reads output (2GB), writes output (2GB)
4. hardtanh: reads output (2GB), writes output (2GB)
5. scale: reads output (2GB), writes output (2GB)
Total memory traffic (after conv): 8GB read + 8GB write = 16GB.
Our fused version: just conv_transpose2d (reads 512MB input, writes 2GB output) + fused elementwise kernel that reads 2GB and writes 2GB = 4.5GB.
Wait, if we fuse elementwise into conv_transpose2d writeback, we'd save even more.
Can we somehow intercept or wrap the conv_transpose2d to fuse the elementwise ops? We can't easily modify cuDNN's kernel.
But we could write a custom autograd.Function or just do the conv in a custom kernel if it's simple enough... but it's not.
Let me think - maybe there's a way to write a more efficient kernel using CUTLASS? For a specific small problem like this, we could write a very efficient implicit GEMM. But that's extremely complex without CUTLASS templates.
Actually, wait. I just realized - convolution transpose can be equivalently expressed as a regular convolution if we permute/dilate the input appropriately. But that doesn't help much.
Another idea: can we use torch.nn.functional.conv2d with a specially prepared input? For deconv with stride=2, we could:
1. Upsample the input by 2x
2. Apply a regular conv2d with appropriate padding
But for exact equivalence, the upsampling would need to insert zeros, not interpolate. And the conv would need kernel=3, padding=1. Let's check:
- Input: 128x128
- Upsample with zeros to 256x256? Actually, insert 1 zero between each pixel: 255x255.
- Pad to 257x257.
- Conv with kernel=3, stride=1, padding=0: output 255x255.
- Then pad to 256x256.
This is getting messy and probably won't be faster than cuDNN's native deconv.
Let me try the fused elementwise approach. Maybe the reference is slow because of Python overhead and separate kernel launches.
Actually, I want to check something. In the reference:
x = self.conv_transpose(x) # one kernel
x = torch.nn.functional.mish(x) # another kernel
x = x + self.add_value # another
x = torch.nn.functional.hardtanh(x, min_val=-1, max_val=1) # another
x = x * self.scale # another
In PyTorch eager mode, these are indeed separate kernel launches. The total overhead is 5 kernel launches plus lots of memory traffic.
A single fused kernel that does: read input -> mish -> add -> hardtanh -> scale -> write output
This would be one kernel launch and only read + write traffic.
But we still need to do the conv_transpose2d first. We can't avoid that unless we fuse everything.
So the best we can do easily is:
y = conv_transpose(x)
return fused_kernel(y)
Or can we? What if we write our own conv_transpose using tensordot or some other PyTorch primitive that's well-optimized, and then fuse everything?
Actually, for deconv with stride=2, we could do:
1. Extract image patches from input (using unfold or a custom kernel)
2. Do a matrix multiplication
3. Reshape and fuse elementwise ops
This is basically what im2col + GEMM does. PyTorch/cuDNN already does this very efficiently.
I think the most realistic approach is a fused elementwise kernel after conv transpose.
Let me code this up and test. We can also try using channels_last memory format or mixed precision, but the problem says fp32 precision.
Wait - one more idea. Since Hardtanh clamps to [-1, 1] and then we multiply by 2:
hardtanh(x + 0.5, -1, 1) * 2
= clamp(x + 0.5, -1, 1) * 2
= clamp(2*(x + 0.5), -2, 2)
= clamp(2*x + 1, -2, 2)
And Mish(x) = x * tanh(softplus(x)) = x * tanh(log(1 + exp(x)))
For large negative x, exp(x) -> 0, so softplus(x) -> 0, tanh(0) -> 0, mish(x) -> 0.
For large positive x, softplus(x) ≈ x, tanh(x) -> 1, mish(x) -> x.
We can implement mish with a numerically stable formula:
mish(x) = x * tanh(log1p(exp(x)))
= x * tanh(softplus(x))
The standard implementation uses:
softplus(x) = log1p(exp(x)) for x < 20, otherwise x
tanh(softplus(x))
But we can use PyTorch's mish formula or the CUDA equivalent.
For the fused kernel, each thread can compute one element.
Let me write the kernel:
```cuda
__global__ void fused_kernel(const float* input, float* output, int n, float add_val, float scale) {
int idx = blockIdx.x * blockDim.x + threadIdx.x;
if (idx >= n) return;
float x = input[idx];
// mish
float sp = log1pf(expf(x)); // softplus, but unstable for large x
// Better:
float sp = x > 20.0f ? x : log1pf(expf(x));
// Even better, use the cuda equivalent of PyTorch's mish
x = x * tanhf(sp);
// add
x = x + add_val;
// hardtanh
x = fminf(1.0f, fmaxf(-1.0f, x));
// scale
x = x * scale;
output[idx] = x;
}
```
Wait, PyTorch's mish is more numerically stable. Let me check how PyTorch implements mish:
```cpp
// From PyTorch source
auto x = self;
auto softplus = at::softplus(x);
auto tanh_softplus = at::tanh(softplus);
return x * tanh_softplus;
```
And softplus is:
```cpp
// for float:
output = input > threshold ? input : std::log1p(std::exp(input));
```
where threshold is typically 20.
And for negative values, exp(input) can underflow, but log1p handles that.
Actually, for very negative x, exp(x) underflows to 0, log1p(0) = 0, tanh(0) = 0, mish(x) = 0. This is fine.
For x around -100: exp(-100) = 0 in float32, log1p(0) = 0. This is fine.
For x = 88, exp(88) overflows in float32. But if x > 20, we use x directly as softplus. So we need to be careful.
Actually, the standard numerically stable softplus is:
```cpp
float softplus(float x) {
if (x > 20.0f) return x;
return log1pf(expf(x));
}
```
This is safe because for x > 20, exp(x) doesn't overflow (exp(88) overflows, but we don't compute exp for x > 20).
Wait, expf(20) = 4.85e8 which doesn't overflow. expf(89) overflows. So we're safe.
For the hardtanh: PyTorch's hardtanh for float is:
```cpp
min_val = -1, max_val = 1
if (x < min_val) return min_val;
else if (x > max_val) return max_val;
else return x;
```
This is equivalent to `fmaxf(min_val, fminf(max_val, x))`.
Now, let me code up the kernel and test.
Actually, maybe we should also consider doing the fused kernel in-place to save memory allocation time. We can do:
```python
x = self.conv_transpose(x)
fused_kernel_(x, add_value, scale)
return x
```
This avoids allocating a new output tensor for the elementwise ops. That saves memory allocation overhead and kernel launch for the copy.
Let me write the first version:
call → compile_kernel
callcompile_kernel
{
"kernel_code": "\nimport torch\nfrom torch.utils.cpp_extension import load_inline\n\ncuda_source = '''\n#include <torch/extension.h>\n#include <cuda_runtime.h>\n#include <math.h>\n\n__global__ void fused_mish_add_hardtanh_scale_kernel(\n const float* __restrict__ input,\n float* __restrict__ output,\n int64_t n,\n float add_val,\n float scale,\n float min_val,\n float max_val) {\n \n int64_t idx = blockIdx.x * blockDim.x + threadIdx.x;\n if (idx >= n) return;\n \n float x = input[idx];\n \n // Mish activation: x * tanh(softplus(x))\n float sp = x > 20.0f ? x : log1pf(expf(x));\n x = x * tanhf(sp);\n \n // Add\n x = x + add_val;\n \n // Hardtanh\n x = fminf(max_val, fmaxf(min_val, x));\n \n // Scale\n x = x * scale;\n \n output[idx] = x;\n}\n\n// In-place version\n__global__ void fused_mish_add_hardtanh_scale_kernel_inplace(\n float* __restrict__ data,\n int64_t n,\n float add_val,\n float scale,\n float min_val,\n float max_val) {\n \n int64_t idx = blockIdx.x * blockDim.x + threadIdx.x;\n if (idx >= n) return;\n \n float x = data[idx];\n \n // Mish activation: x * tanh(softplus(x))\n float sp = x > 20.0f ? x : log1pf(expf(x));\n x = x * tanhf(sp);\n \n // Add\n x = x + add_val;\n \n // Hardtanh\n x = fminf(max_val, fmaxf(min_val, x));\n \n // Scale\n x = x * scale;\n \n data[idx] = x;\n}\n\ntorch::Tensor fused_mish_add_hardtanh_scale(\n torch::Tensor input,\n float add_val,\n float scale,\n float min_val,\n float max_val) {\n \n auto output = torch::empty_like(input);\n int64_t n = input.numel();\n \n const int threads = 256;\n const int blocks = (n + threads - 1) / threads;\n \n fused_mish_add_hardtanh_scale_kernel<<<blocks, threads>>>(\n input.data_ptr<float>(),\n output.data_ptr<float>(),\n n,\n add_val,\n scale,\n min_val,\n max_val\n );\n \n return output;\n}\n\ntorch::Tensor fused_mish_add_hardtanh_scale_inplace(\n torch::Tensor input,\n float add_val,\n float scale,\n float min_val,\n float max_val) {\n \n int64_t n = input.numel();\n \n const int threads = 256;\n const int blocks = (n + threads - 1) / threads;\n \n fused_mish_add_hardtanh_scale_kernel_inplace<<<blocks, threads>>>(\n input.data_ptr<float>(),\n n,\n add_val,\n scale,\n min_val,\n max_val\n );\n \n return input;\n}\n'''\n\ncpp_source = '''\ntorch::Tensor fused_mish_add_hardtanh_scale(\n torch::Tensor input,\n float add_val,\n float scale,\n float min_val,\n float max_val);\n\ntorch::Tensor fused_mish_add_hardtanh_scale_inplace(\n torch::Tensor input,\n float add_val,\n float scale,\n float min_val,\n float max_val);\n'''\n\n# Load the inline CUDA extension\nfused_ops = load_inline(\n name=\"fused_ops\",\n cpp_sources=cpp_source,\n cuda_sources=cuda_source,\n functions=[\"fused_mish_add_hardtanh_scale\", \"fused_mish_add_hardtanh_scale_inplace\"],\n extra_cuda_cflags=[\"-O3\"],\n verbose=False\n)\n\nclass ModelNew(torch.nn.Module):\n def __init__(self, in_channels, out_channels, kernel_size, stride, padding, output_padding, add_value, scale):\n super(ModelNew, self).__init__()\n self.conv_transpose = torch.nn.ConvTranspose2d(in_channels, out_channels, kernel_size, stride, padding, output_padding)\n self.add_value = add_value\n self.scale = scale\n\n def forward(self, x):\n x = self.conv_transpose(x)\n x = fused_ops.fused_mish_add_hardtanh_scale_inplace(x, self.add_value, self.scale, -1.0, 1.0)\n return x\n"
}